Benutzer:Scl200

Bei der Tasse handelt es sich um einen Kegelstumpf

Oberfläche

$O = π ⋆ (r_{1})^{2} + π ⋆ (r_{2})^{2} + (r_{1} + r_{2}) ⋆ π ⋆ m$

Höhe

$\sqrt{m^{2} - (r_{1} - r_{2})^{2}}$

Volumen

$V = \frac{(h ⋆ π)}{3} ⋆ ((r_{1})^{2} + r_{1} ⋆ r_{2} + (r_{2})^{2})$

Berechnung

$m = 11 c m$

$d_{1} = 9 c m \to r_{1} = 4, 5 c m$

$d_{2} = 6, 5 c m \to r_{2} = 3, 25 c m$

$O = π ⋆ 4, 52 + π ⋆ 3, 252 + (4, 5 + 3, 25) ⋆ π ⋆ 11 \approx 364, 62 c m$

$h = \sqrt{1 1^{2} - (4, 5_{1} - 3, 2 5_{2})^{2}} \approx 10, 9 c m$

$V = \frac{(10, 9 ⋆ π)}{3} ⋆ ((4, 5)^{2} + 4, 5 ⋆ 3, 25 + (3, 25)^{2}) \approx 518, 64 c m^{2}$

Navigation